Subelement A: RADAR Principles – 10 Key Topics – 10 Exam Questions – 8 Drawings— Topic 4: Power, Pulse Width, PRR
Question 8-4A6
Element 8 (RADAR)A search RADAR has a pulse width of 1.0 microsecond, a pulse repetition frequency (PRF) of 900 Hz, and an average power of 18 watts. The unit’s peak power is:
Explanation
In a pulsed radar system, the average power is the product of its peak power and its duty cycle. The duty cycle represents the fraction of time the transmitter is actively transmitting, calculated by multiplying the pulse width by the pulse repetition frequency (PRF).
First, calculate the duty cycle (DC):
DC = Pulse Width $\times$ PRF
DC = $1.0 \times 10^{-6}$ seconds $\times$ 900 Hz = 0.0009
Next, use the formula relating average power and peak power:
Average Power = Peak Power $\times$ Duty Cycle
Rearranging to solve for Peak Power:
Peak Power = Average Power / Duty Cycle
Peak Power = 18 watts / 0.0009 = 20,000 watts
Converting to kilowatts:
20,000 watts = 20 kilowatts.
Related Questions
8-4A4 If a RADAR transmitter has a pulse repetition frequency (PRF) of 900 Hz, a pulse width of 0.5 microseconds and a peak power of 15 kilowatts, what is its average power output?8-4A5 What is the average power if the RADAR set has a PRF of 1000 Hz, a pulse width of 1 microsecond, and a peak power rating of 100 kilowatts?8-50F1 Choose the most correct statement with respect to component damage from electrostatic discharge:8-50F2 Before testing a RADAR transmitter, it would be a good idea to:8-50F3 While making repairs or adjustments to RADAR units: