Subelement A: — Topic :
Question 6A79
Element 6 (Radiotelegraph)How many capacitors of 400 volts and 2 microfarad each would be necessary to obtain a combinationrated at 1600 volts and 1.5 microfarad?
Explanation
To achieve a higher voltage rating, capacitors must be connected in series. The total voltage rating for capacitors in series is the sum of the individual voltage ratings.
Desired voltage = 1600 V
Individual capacitor voltage = 400 V
Number of capacitors in series (N_s) = 1600 V / 400 V = 4 capacitors.
When capacitors are connected in series, their total capacitance decreases. For N_s equal capacitors in series, the total capacitance of that string is C_string = C_individual / N_s.
C_string = 2 microfarad / 4 = 0.5 microfarad.
We need a total capacitance of 1.5 microfarad. To increase capacitance, strings of capacitors must be connected in parallel.
Number of parallel strings (N_p) = Desired total capacitance / Capacitance of one string
N_p = 1.5 microfarad / 0.5 microfarad = 3 parallel strings.
Therefore, we need 3 parallel strings, with each string containing 4 capacitors in series.
Total number of capacitors = N_s * N_p = 4 capacitors/string * 3 strings = 12 capacitors.
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