Subelement A: — Topic :
Question 6A73
Element 6 (Radiotelegraph)Given: Input power to a receiver is 75 watts. How much power does the receiver consume in 24 hours ofcontinuous operation?
Explanation
The question asks for the total energy consumed by the receiver over a period, not its instantaneous power. Energy consumed is calculated by multiplying power by time.
Given: Input Power (P) = 75 watts, Time (t) = 24 hours.
Energy (E) = P × t = 75 watts × 24 hours = 1800 watthours (Wh).
This calculation matches option A.
To express this energy in kilowatthours (kWh), we convert watthours to kilowatthours by dividing by 1000 (since 1 kilowatt = 1000 watts).
E = 1800 Wh / 1000 = 1.80 kilowatthours (kWh).
This conversion matches option B.
Both 1800 watthours and 1.80 kilowatthours represent the exact same amount of electrical energy consumed, just expressed using different units. Therefore, both A and B are correct statements, making C the comprehensive correct answer. This demonstrates a fundamental understanding of electrical energy calculation and unit conversion, crucial for evaluating power usage in amateur radio stations.
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