Question 6A530

AC voltmeters typically display the Root Mean Square (RMS) value of a sinusoidal waveform. The RMS value represents the effective voltage, meaning it would produce the same heating effect in a resistive load as an equivalent DC voltage. For a pure sine wave, the relationship between the peak voltage ($V_p$) and the RMS voltage ($V_{RMS}$) is given by: $V_p = V_{RMS} \times \sqrt{2}$ Therefore, to convert the RMS reading shown on an AC voltmeter to its peak value, you must multiply the reading by $\sqrt{2}$. The value of $\sqrt{2}$ is approximately 1.414. Options A, C, and D are incorrect. Option C ($1/\sqrt{2}$) would convert peak voltage to RMS voltage. Options A (141) and D (2) are incorrect factors for this conversion.