Subelement B: Electrical Math— Topic 12: Waveforms
Question 3-12B2
Element 3 (GROL)At 150 degrees, what is the amplitude of a sine-wave having a peak value of 5 volts?
Explanation
The instantaneous amplitude of a sine wave is determined by its peak value and the sine of its phase angle. The formula is:
Amplitude = Peak Value × sin(angle)
In this case, the peak value is 5 volts and the angle is 150 degrees.
* Calculate sin(150°): sin(150°) = 0.5
* Multiply by the peak value: 5 volts × 0.5 = 2.5 volts
Therefore, at 150 degrees, the amplitude of the sine wave is +2.5 volts.
Option B (-2.5 volts) would be correct if the angle were 210 degrees (or -30 degrees), where sin(210°) = -0.5. Options A and D represent different magnitudes, which would occur at angles where the sine function has a different absolute value (e.g., approximately 60 or 120 degrees for +4.3 volts).
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